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Memorize

3D Distance Formula

Pythagorean theorem applied twice. Identical to 2D, just with a z-term added.

d=(x2​−x1​)2+(y2​−y1​)2+(z2​−z1​)2​

2D formula + $(z_2-z_1)^2$ inside the root

Δx,Δy,Δz

Coordinate diffs

Subtract corresponding coordinates

Square & add

Δx2+Δy2+Δz2

Sum of squares

​

Take square root

Result is the distance